Optimal. Leaf size=296 \[ \frac{4 i b^{5/2} p^2 \text{PolyLog}\left (2,1-\frac{2 \sqrt{a}}{\sqrt{a}+i \sqrt{b} x}\right )}{5 a^{5/2}}+\frac{4 b^2 p \log \left (c \left (a+b x^2\right )^p\right )}{5 a^2 x}+\frac{4 b^{5/2} p \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right ) \log \left (c \left (a+b x^2\right )^p\right )}{5 a^{5/2}}-\frac{8 b^2 p^2}{15 a^2 x}+\frac{4 i b^{5/2} p^2 \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )^2}{5 a^{5/2}}-\frac{32 b^{5/2} p^2 \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )}{15 a^{5/2}}+\frac{8 b^{5/2} p^2 \log \left (\frac{2 \sqrt{a}}{\sqrt{a}+i \sqrt{b} x}\right ) \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )}{5 a^{5/2}}-\frac{\log ^2\left (c \left (a+b x^2\right )^p\right )}{5 x^5}-\frac{4 b p \log \left (c \left (a+b x^2\right )^p\right )}{15 a x^3} \]
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Rubi [A] time = 0.32035, antiderivative size = 296, normalized size of antiderivative = 1., number of steps used = 14, number of rules used = 11, integrand size = 18, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.611, Rules used = {2457, 2476, 2455, 325, 205, 2470, 12, 4920, 4854, 2402, 2315} \[ \frac{4 i b^{5/2} p^2 \text{PolyLog}\left (2,1-\frac{2 \sqrt{a}}{\sqrt{a}+i \sqrt{b} x}\right )}{5 a^{5/2}}+\frac{4 b^2 p \log \left (c \left (a+b x^2\right )^p\right )}{5 a^2 x}+\frac{4 b^{5/2} p \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right ) \log \left (c \left (a+b x^2\right )^p\right )}{5 a^{5/2}}-\frac{8 b^2 p^2}{15 a^2 x}+\frac{4 i b^{5/2} p^2 \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )^2}{5 a^{5/2}}-\frac{32 b^{5/2} p^2 \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )}{15 a^{5/2}}+\frac{8 b^{5/2} p^2 \log \left (\frac{2 \sqrt{a}}{\sqrt{a}+i \sqrt{b} x}\right ) \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )}{5 a^{5/2}}-\frac{\log ^2\left (c \left (a+b x^2\right )^p\right )}{5 x^5}-\frac{4 b p \log \left (c \left (a+b x^2\right )^p\right )}{15 a x^3} \]
Antiderivative was successfully verified.
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Rule 2457
Rule 2476
Rule 2455
Rule 325
Rule 205
Rule 2470
Rule 12
Rule 4920
Rule 4854
Rule 2402
Rule 2315
Rubi steps
\begin{align*} \int \frac{\log ^2\left (c \left (a+b x^2\right )^p\right )}{x^6} \, dx &=-\frac{\log ^2\left (c \left (a+b x^2\right )^p\right )}{5 x^5}+\frac{1}{5} (4 b p) \int \frac{\log \left (c \left (a+b x^2\right )^p\right )}{x^4 \left (a+b x^2\right )} \, dx\\ &=-\frac{\log ^2\left (c \left (a+b x^2\right )^p\right )}{5 x^5}+\frac{1}{5} (4 b p) \int \left (\frac{\log \left (c \left (a+b x^2\right )^p\right )}{a x^4}-\frac{b \log \left (c \left (a+b x^2\right )^p\right )}{a^2 x^2}+\frac{b^2 \log \left (c \left (a+b x^2\right )^p\right )}{a^2 \left (a+b x^2\right )}\right ) \, dx\\ &=-\frac{\log ^2\left (c \left (a+b x^2\right )^p\right )}{5 x^5}+\frac{(4 b p) \int \frac{\log \left (c \left (a+b x^2\right )^p\right )}{x^4} \, dx}{5 a}-\frac{\left (4 b^2 p\right ) \int \frac{\log \left (c \left (a+b x^2\right )^p\right )}{x^2} \, dx}{5 a^2}+\frac{\left (4 b^3 p\right ) \int \frac{\log \left (c \left (a+b x^2\right )^p\right )}{a+b x^2} \, dx}{5 a^2}\\ &=-\frac{4 b p \log \left (c \left (a+b x^2\right )^p\right )}{15 a x^3}+\frac{4 b^2 p \log \left (c \left (a+b x^2\right )^p\right )}{5 a^2 x}+\frac{4 b^{5/2} p \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right ) \log \left (c \left (a+b x^2\right )^p\right )}{5 a^{5/2}}-\frac{\log ^2\left (c \left (a+b x^2\right )^p\right )}{5 x^5}+\frac{\left (8 b^2 p^2\right ) \int \frac{1}{x^2 \left (a+b x^2\right )} \, dx}{15 a}-\frac{\left (8 b^3 p^2\right ) \int \frac{1}{a+b x^2} \, dx}{5 a^2}-\frac{\left (8 b^4 p^2\right ) \int \frac{x \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )}{\sqrt{a} \sqrt{b} \left (a+b x^2\right )} \, dx}{5 a^2}\\ &=-\frac{8 b^2 p^2}{15 a^2 x}-\frac{8 b^{5/2} p^2 \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )}{5 a^{5/2}}-\frac{4 b p \log \left (c \left (a+b x^2\right )^p\right )}{15 a x^3}+\frac{4 b^2 p \log \left (c \left (a+b x^2\right )^p\right )}{5 a^2 x}+\frac{4 b^{5/2} p \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right ) \log \left (c \left (a+b x^2\right )^p\right )}{5 a^{5/2}}-\frac{\log ^2\left (c \left (a+b x^2\right )^p\right )}{5 x^5}-\frac{\left (8 b^3 p^2\right ) \int \frac{1}{a+b x^2} \, dx}{15 a^2}-\frac{\left (8 b^{7/2} p^2\right ) \int \frac{x \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )}{a+b x^2} \, dx}{5 a^{5/2}}\\ &=-\frac{8 b^2 p^2}{15 a^2 x}-\frac{32 b^{5/2} p^2 \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )}{15 a^{5/2}}+\frac{4 i b^{5/2} p^2 \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )^2}{5 a^{5/2}}-\frac{4 b p \log \left (c \left (a+b x^2\right )^p\right )}{15 a x^3}+\frac{4 b^2 p \log \left (c \left (a+b x^2\right )^p\right )}{5 a^2 x}+\frac{4 b^{5/2} p \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right ) \log \left (c \left (a+b x^2\right )^p\right )}{5 a^{5/2}}-\frac{\log ^2\left (c \left (a+b x^2\right )^p\right )}{5 x^5}+\frac{\left (8 b^3 p^2\right ) \int \frac{\tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )}{i-\frac{\sqrt{b} x}{\sqrt{a}}} \, dx}{5 a^3}\\ &=-\frac{8 b^2 p^2}{15 a^2 x}-\frac{32 b^{5/2} p^2 \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )}{15 a^{5/2}}+\frac{4 i b^{5/2} p^2 \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )^2}{5 a^{5/2}}+\frac{8 b^{5/2} p^2 \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right ) \log \left (\frac{2 \sqrt{a}}{\sqrt{a}+i \sqrt{b} x}\right )}{5 a^{5/2}}-\frac{4 b p \log \left (c \left (a+b x^2\right )^p\right )}{15 a x^3}+\frac{4 b^2 p \log \left (c \left (a+b x^2\right )^p\right )}{5 a^2 x}+\frac{4 b^{5/2} p \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right ) \log \left (c \left (a+b x^2\right )^p\right )}{5 a^{5/2}}-\frac{\log ^2\left (c \left (a+b x^2\right )^p\right )}{5 x^5}-\frac{\left (8 b^3 p^2\right ) \int \frac{\log \left (\frac{2}{1+\frac{i \sqrt{b} x}{\sqrt{a}}}\right )}{1+\frac{b x^2}{a}} \, dx}{5 a^3}\\ &=-\frac{8 b^2 p^2}{15 a^2 x}-\frac{32 b^{5/2} p^2 \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )}{15 a^{5/2}}+\frac{4 i b^{5/2} p^2 \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )^2}{5 a^{5/2}}+\frac{8 b^{5/2} p^2 \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right ) \log \left (\frac{2 \sqrt{a}}{\sqrt{a}+i \sqrt{b} x}\right )}{5 a^{5/2}}-\frac{4 b p \log \left (c \left (a+b x^2\right )^p\right )}{15 a x^3}+\frac{4 b^2 p \log \left (c \left (a+b x^2\right )^p\right )}{5 a^2 x}+\frac{4 b^{5/2} p \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right ) \log \left (c \left (a+b x^2\right )^p\right )}{5 a^{5/2}}-\frac{\log ^2\left (c \left (a+b x^2\right )^p\right )}{5 x^5}+\frac{\left (8 i b^{5/2} p^2\right ) \operatorname{Subst}\left (\int \frac{\log (2 x)}{1-2 x} \, dx,x,\frac{1}{1+\frac{i \sqrt{b} x}{\sqrt{a}}}\right )}{5 a^{5/2}}\\ &=-\frac{8 b^2 p^2}{15 a^2 x}-\frac{32 b^{5/2} p^2 \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )}{15 a^{5/2}}+\frac{4 i b^{5/2} p^2 \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )^2}{5 a^{5/2}}+\frac{8 b^{5/2} p^2 \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right ) \log \left (\frac{2 \sqrt{a}}{\sqrt{a}+i \sqrt{b} x}\right )}{5 a^{5/2}}-\frac{4 b p \log \left (c \left (a+b x^2\right )^p\right )}{15 a x^3}+\frac{4 b^2 p \log \left (c \left (a+b x^2\right )^p\right )}{5 a^2 x}+\frac{4 b^{5/2} p \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right ) \log \left (c \left (a+b x^2\right )^p\right )}{5 a^{5/2}}-\frac{\log ^2\left (c \left (a+b x^2\right )^p\right )}{5 x^5}+\frac{4 i b^{5/2} p^2 \text{Li}_2\left (1-\frac{2 \sqrt{a}}{\sqrt{a}+i \sqrt{b} x}\right )}{5 a^{5/2}}\\ \end{align*}
Mathematica [C] time = 0.27216, size = 277, normalized size = 0.94 \[ -\frac{3 \log ^2\left (c \left (a+b x^2\right )^p\right )+\frac{4 b p x^2 \left (-3 i b^{3/2} p x^3 \left (\text{PolyLog}\left (2,\frac{\sqrt{b} x+i \sqrt{a}}{\sqrt{b} x-i \sqrt{a}}\right )+\tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right ) \left (\tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )-2 i \log \left (\frac{2 \sqrt{a}}{\sqrt{a}+i \sqrt{b} x}\right )\right )\right )+a^{3/2} \log \left (c \left (a+b x^2\right )^p\right )-3 b^{3/2} x^3 \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right ) \log \left (c \left (a+b x^2\right )^p\right )+6 b^{3/2} p x^3 \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )-3 \sqrt{a} b x^2 \log \left (c \left (a+b x^2\right )^p\right )+2 \sqrt{a} b p x^2 \, _2F_1\left (-\frac{1}{2},1;\frac{1}{2};-\frac{b x^2}{a}\right )\right )}{a^{5/2}}}{15 x^5} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.963, size = 0, normalized size = 0. \begin{align*} \int{\frac{ \left ( \ln \left ( c \left ( b{x}^{2}+a \right ) ^{p} \right ) \right ) ^{2}}{{x}^{6}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\log \left ({\left (b x^{2} + a\right )}^{p} c\right )^{2}}{x^{6}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\log \left ({\left (b x^{2} + a\right )}^{p} c\right )^{2}}{x^{6}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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